5x^2+25x=-20x-70

Solution for 5x^2+25x=-20x-70 equation:

5x^2+25x=-20x-70

We move all terms to the left:

5x^2+25x-(-20x-70)=0

We get rid of parentheses

5x^2+25x+20x+70=0

We add all the numbers together, and all the variables

5x^2+45x+70=0

a = 5; b = 45; c = +70;
Δ = b2-4ac
Δ = 452-4·5·70
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-25}{2*5}=\frac{-70}{10}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+25}{2*5}=\frac{-20}{10}
=-2
$